x^2-3x=x(3+x)

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Solution for x^2-3x=x(3+x) equation: 



x^2-3x=x(3+x)

We move all terms to the left:

x^2-3x-(x(3+x))=0

We add all the numbers together, and all the variables

x^2-3x-(x(x+3))=0



We calculate terms in parentheses: -(x(x+3)), so:

x(x+3)

We multiply parentheses

x^2+3x

Back to the equation:

-(x^2+3x)



We get rid of parentheses

x^2-x^2-3x-3x=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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